Use BE: H–H = 436, Cl–Cl = 243, H–Cl = 431 kJ/mol. ΔH for H₂ + Cl₂ → 2 HCl ≈
- A
+183 kJ
- B
−679 kJ
- Ccheck_circle
−183 kJ
- D
+679 kJ
Explanation
Broken: 436 + 243 = 679. Formed: 2·431 = 862. ΔH ≈ 679 − 862 = −183 kJ.
Bond Enthalpies
AP Chemistry· difficulty 4/5
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