For H₂(g) + Cl₂(g) → 2 HCl(g)
Using bond energies (kJ/mol), what is ΔH for the reaction?
- A
+679 kJ
- Bcheck_circle
-185 kJ
- C
-247 kJ
- D
+185 kJ
Explanation
ΔH = (bonds broken) - (bonds formed) = (436 + 243) - 2(432) = 679 - 864 = -185 kJ.
Bond Enthalpies
AP Chemistry· difficulty 3/5
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