Bond Enthalpies

AP Chemistry· difficulty 4/5

_2

A
$+185 kJ$
B
$-679 kJ$
C
$-247 kJ (sum bonds broken - sum bonds formed)$
D
$-185 kJ$
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Explanation

ΔH = (bonds broken) - (bonds formed) = (436 + 243) - 2(432) = 679 - 864 = -185 kJ.

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