Bond Enthalpies

AP Chemistry· difficulty 3/5

Using bond enthalpies (kJ/mol): H-H 436, Cl-Cl 243, H-Cl 432. For H₂ + Cl₂ \to 2 HCl, ΔH \approx

A
$+247$
B
$-185$
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C
$-247$
D
$+185$

Explanation

Bonds broken: 436 + 243 = 679. Bonds formed: 2 \times 432 = 864. ΔH \approx 679 - 864 = -185 kJ/mol (exothermic).

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