Two Arrhenius plots are compared: reaction A has slope −5000 K, reaction B has slope −10000 K.
Which reaction is more sensitive to temperature change, and why?
- A
A, because A starts at higher ln k.
- B
Both are equally sensitive.
- C
A, because shallower slope means stronger T dependence.
- Dcheck_circle
B, because steeper |slope| means larger Eₐ.
Explanation
Slope = −Eₐ/R; steeper (more negative) slope means larger Eₐ, so k changes more dramatically with T. B is more T-sensitive.