AP Chemistry· difficulty 3/5
The Arrhenius equation linearized: ln k = -Ea/(RT) + ln A. The plot of ln k vs 1/T has slope -1.20 × 10^4 K.
What is the activation energy? (R = 8.314 J/mol·K)
99.8 kJ/mol
8.31 kJ/mol
12.0 kJ/mol
1200 kJ/mol
Explanation
Ea = -slope × R = (1.20 × 10^4 K)(8.314 J/mol·K) ≈ 9.98 × 10^4 J/mol ≈ 99.8 kJ/mol.
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