For the Daniell cell (E^\circ = 1.10 V) at 298 K with [Zn^{2+}] = 1.0 M and [Cu^{2+}] = 0.0010 M, calculate E{cell}.

Question

Accepted Answer

E{cell} \approx 1.01 V

E = E^\circ - (0.0592/n)\log Q. n = 2; Q = [Zn^{2+}]/[Cu^{2+}] = 1000. E = 1.10 - (0.0296)(3) = 1.10 - 0.0888 = 1.01 V.

Answer

E{cell} \approx 1.10 V

Answer

E{cell} \approx 0.92 V

Answer

E{cell} \approx 1.19 V

Answer

E{cell} \approx 1.01 V

Cell Potential Under Nonstandard Conditions