Nernst equation: E = E° − (RT/nF) ln Q. At 25 °C this becomes
- A
E = E° − (0.0592 n) log Q
- Bcheck_circle
E = E° − (0.0592/n) log Q
- C
E = E° + (0.0592/n) log Q
- D
E = E° − ln Q
Explanation
With T = 298 K and conversion to log: 0.0592/n.
AP Chemistry· difficulty 4/5
Nernst equation: E = E° − (RT/nF) ln Q. At 25 °C this becomes
E = E° − (0.0592 n) log Q
E = E° − (0.0592/n) log Q
E = E° + (0.0592/n) log Q
E = E° − ln Q
Explanation
With T = 298 K and conversion to log: 0.0592/n.
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