AP Chemistry· difficulty 4/5
Zn|Zn²⁺ || Cu²⁺|Cu cell; Q = [Zn²⁺]/[Cu²⁺].
Increasing [Cu²⁺] (decreasing Q) does what to E_cell?
Reverses cell polarity
Decreases E_cell below E°
Increases E_cell above E°
Has no effect
Explanation
Smaller Q → ln Q < 0 → -(RT/nF)ln Q > 0, raising E above E°cell.
Want 10 more like this — adaptive to your weak spots?
A concentration cell with [Cu²⁺] differing on two sides will produce voltage that is…
chevron_rightFor the Daniell cell (E^\circ = 1.10 V) at 298 K with [Zn^{2+}] = 1.0 M and [Cu^{2+}] = 0.0010 M, calculate E{cell}.…
chevron_rightFor Q 1, why does the Nernst plot show E decreasing as T increases?…
chevron_right