Cell Potential Under Nonstandard Conditions

AP Chemistry· difficulty 3/5

A student builds a Cu concentration cell with two Cu electrodes immersed in 0.0010 M and 1.00 M Cu(NO3)2 with a salt bridge. At 25 C the measured cell potential is +0.088 V (left half-cell positive). E^o for the same metal in both half-cells is 0 V; the Nernst equation gives E_cell = -(0.0592/2) * log(Q).

Cu Cu 0.0010 M Cu2+ 1.00 M Cu2+ salt bridge V +0.088 V

Which electrode is the cathode?

  • A

    the Cu electrode in 0.0010 M Cu^2+

  • B

    the Cu electrode in 1.00 M Cu^2+

    check_circle
  • C

    both function as cathodes simultaneously

  • D

    neither - the cell is at equilibrium

Explanation

Reduction of Cu^2+ -> Cu is favored where [Cu^2+] is greater. The cathode is the electrode in 1.00 M Cu^2+.

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