If f(x)=1/x2f(x) = 1/x^2f(x)=1/x2, then f′(x)=f'(x) =f′(x)=A2/x32/x^32/x3B−1/x3-1/x^3−1/x3C1/(2x)1/(2x)1/(2x)D−2/x3-2/x^3−2/x3check_circleExplanation1/x2=x−21/x^2 = x^{-2}1/x2=x−2. f′(x)=−2x−3=−2/x3f'(x) = -2 x^{-3} = -2/x^3f′(x)=−2x−3=−2/x3.