For f(x)=6−2x+x2f(x) = 6 - 2x + x^2f(x)=6−2x+x2, f′(1)=f'(1) =f′(1)=A111B222C000check_circleD555Explanationf′(x)=−2+2xf'(x) = -2 + 2xf′(x)=−2+2x. f′(1)=0f'(1) = 0f′(1)=0.