Applying the Power Rule

AP Calculus AB· difficulty 2/5

\dfrac{d}{dx}\bigl(x^{2/3}\bigr) =

A
$\tfrac{2}{3} x^{1/3}$
B
$\tfrac{3}{2} x^{1/3}$
C
$\tfrac{3}{2} x^{-1/3}$
D
$\tfrac{2}{3} x^{-1/3}$
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Explanation

\tfrac{2}{3} x^{2/3 - 1} = \tfrac{2}{3} x^{-1/3}

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