The velocity-vs-time graph shows an object starting from rest and accelerating uniformly. What is the total displacement of the object over the 10\text{s} interval?

100\text{m} Displacement equals the area under the v–t curve: a triangle of base 10\text{s} and height 20\text{m/s}, giving \tfrac{1}{2}(10)(20) = 100\text{m}.

school

Acemy

Representing Motion

AP Physics 1· difficulty 2/5

10~\text{s}

A
$50~\text{m}$
B
$100~\text{m}$
check_circle
C
$200~\text{m}$
D
$150~\text{m}$

Explanation

v

Want 10 more like this — adaptive to your weak spots?

Practice 10 like thisarrow_forward Predict my AP score

Related questions