Representing Motion

AP Physics 1· difficulty 2/5

On a vv-vs-tt graph, an object's curve is a horizontal straight line at v=8 m/sv = -8~\text{m/s}. Its acceleration is

  • A

    Cannot be determined

  • B

    8 m/s2-8~\text{m/s}^2

  • C

    00

    check_circle
  • D

    +8 m/s2+8~\text{m/s}^2

Explanation

Slope of vv-vs-tt is acceleration. A horizontal line has slope zero, regardless of vv's sign.

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