Representing Motion

AP Physics 1· difficulty 3/5

+v −v 0 2 4

The vv-vs-tt graph shows symmetric positive and negative phases over 4 s4~\text{s}. The total <strong>distance</strong> traveled is 8 m8~\text{m}. What is the net <strong>displacement</strong>?

  • A

    +4 m+4~\text{m}

  • B

    4 m-4~\text{m}

  • C

    00

    check_circle
  • D

    +8 m+8~\text{m}

Explanation

Equal positive and negative areas under vv-vs-tt cancel, giving zero net displacement.

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