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Circular Motion

AP Physics 1· difficulty 4/5

A conical pendulum of length L=1L = 1 m sweeps a circle at half- angle 30° from vertical. The period is approximately

  • A

    1.871.87 s

    check_circle
  • B

    0.50.5 s

  • C

    2π2\pi s

  • D

    3.03.0 s

Explanation

T=2πLcos⁡θ/g=2π1⋅cos⁡30°/9.8T = 2\pi\sqrt{L\cos\theta/g} = 2\pi\sqrt{1\cdot\cos 30°/9.8} =2π0.0884≈2π(0.297)≈1.87= 2\pi\sqrt{0.0884} ≈ 2\pi(0.297) ≈ 1.87 s.

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