A car loops in a vertical circle of radius R = 8.0\text{ m}. What minimum speed at the top keeps the car in contact with the track? Use g = 9.8\text{ m/s}^2.

8.85 m/s At the top, gravity supplies the centripetal force at minimum: mg = mv^2/R, so v = \sqrt{gR} = \sqrt{9.8 \times 8} \approx \sqrt{78.4} \approx 8.85\text{ m/s}.

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Acemy

Circular Motion

AP Physics 1· difficulty 4/5

R = 8.0\text{ m}

A
$12.5 m/s$
B
$6.26 m/s$
C
$9.80 m/s$
D
$8.85 m/s$
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Explanation

mg = mv^2/R

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