Circular Motion

AP Physics 1· difficulty 4/5

m₁ m₂

A frictionless Atwood machine has m1=4.0 kgm_1 = 4.0\text{ kg} and m2=6.0 kgm_2 = 6.0\text{ kg}. What is the magnitude of the system's acceleration? Use g=9.8 m/s2g = 9.8\text{ m/s}^2.

  • A

    1.96 m/s²

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  • B

    2.45 m/s²

  • C

    0.98 m/s²

  • D

    3.92 m/s²

Explanation

Atwood acceleration: a=(m2m1)g/(m1+m2)=2(9.8)/10=1.96 m/s2a = (m_2 - m_1)g/(m_1 + m_2) = 2(9.8)/10 = 1.96\text{ m/s}^2.

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