Question

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Find Angle GJO Given Angles 21°, 33°, 42° in a Circle

Original question: 14. GHO and JIO are triangles. Angle OGH = 21°. Angle OIJ = 42°. Angle JGO = 33°. Find the size of angle GJO. J G 210 210 1170630 42° I 420 H

Expert Verified Solution

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Answer

Based on the geometric properties of the circle provided, the size of angle GJO\angle GJO is 2121^\circ. This result is derived using the "Angles in the Same Segment" theorem, which states that angles subtended by the same arc at the circumference are equal.

Explanation

The image shows a circle containing four points (G,H,I,JG, H, I, J) on the circumference. There are two intersecting chords, GIGI and JHJH, which meet at point OO. Your handwritten notes correctly identify several supplementary and vertical angles around point OO, but to find GJO\angle GJO, we must look at the arcs.

  1. Identify the arc subtending the required angle The angle we need to find is GJO\angle GJO. This angle is an inscribed angle that "opens up" to arc GOGO. ⚠️ This step is required on exams to justify which circle theorem you are applying.

  2. Find other angles subtended by the same arc Look for any other angle on the circumference that subtends the same arc GOGO. Following the lines from GG and OO to the circumference, we see that GHO\angle GHO (or GHI\angle GHI) also subtends arc GOGO. However, the value for GHO\angle GHO is not immediately given. Instead, let's look at arc HIHI.

  3. Apply the "Angles in the Same Segment" theorem The theorem states that angles subtended by the same arc at the circumference are equal. Angle GJO=Angle GHO(subtended by arc GO) \text{Angle } GJO = \text{Angle } GHO \quad (\text{subtended by arc } GO) Angle OGH=Angle OJI(subtended by arc HI) \text{Angle } OGH = \text{Angle } OJI \quad (\text{subtended by arc } HI) Angle OIJ=Angle OGH ? No, check the shared arc. \text{Angle } OIJ = \text{Angle } OGH \text{ ? No, check the shared arc.} Let's re-examine arc GHGH. Both GIH\angle GIH and GJH\angle GJH subtend arc GHGH. Let's re-examine arc JIJI. Both JGI\angle JGI and JHI\angle JHI subtend arc JIJI. Let's re-examine arc HIHI. Both HGI\angle HGI and HJI\angle HJI subtend arc HIHI. From the given information: OGH=21\angle OGH = 21^\circ This angle OGH\angle OGH (or IGH\angle IGH) subtends arc HIHI. Another angle subtending arc HIHI is HJI\angle HJI (or OJI\angle OJI). OJI=OGH=21\angle OJI = \angle OGH = 21^\circ This formula establishes that inscribed angles starting and ending at the same points on the circle's edge are identical in measure.

  4. Solve for the specific requested angle The question asks for GJO\angle GJO. We look at arc GHGH. The angles subtended by arc GHGH are GIH\angle GIH and GJH\angle GJH. From the prompt, OIJ\angle OIJ is given as 4242^\circ. This angle subtends arc GJGJ. Another angle subtending arc GJGJ is GHJ\angle GHJ. Wait, let's look at arc GIGI. The angles subtending arc GIGI are GJI\angle GJI and GHI\angle GHI. Actually, looking specifically at arc HIHI: HGI=21\angle HGI = 21^\circ (given). Therefore, HJI=21\angle HJI = 21^\circ (angles in the same segment). Note that HJI\angle HJI is the same as OJI\angle OJI. Searching for GJO\angle GJO: it subtends arc GOGO. Looking at the diagram, GHO\angle GHO also subtends arc GOGO. Since the triangles are formed by chords: GJO=GHO\angle GJO = \angle GHO In Triangle GHOGHO, we can find GHO\angle GHO if we know the other angles. However, there is a simpler path. Look at arc IJIJ. The angles subtending it are IGJ\angle IGJ and IHJ\angle IHJ. IGJ=33    IHJ=33\angle IGJ = 33^\circ \implies \angle IHJ = 33^\circ Look at arc GHGH. The angles subtending it are GIH\angle GIH and GJH\angle GJH. The angle GIH\angle GIH is not explicitly given, but we have OIJ=42\angle OIJ = 42^\circ (subtends arc GJGJ). Therefore, GHJ\angle GHJ must also be 4242^\circ. Finally, for GJO\angle GJO, we look at arc GOGO. This is equal to GHO\angle GHO. In Triangle OGHOGH: GHO=180Angle GOHAngle OGH\angle GHO = 180^\circ - \text{Angle } GOH - \text{Angle } OGH From your handwriting, GOH=117\angle GOH = 117^\circ. GHO=18011721=42\angle GHO = 180^\circ - 117^\circ - 21^\circ = 42^\circ The sum of interior angles in any triangle must equal 180 degrees.

  5. Final Calculation Since GJO=GHO\angle GJO = \angle GHO: GJO=42\angle GJO = 42^\circ This numerical value represents the degree measure of the angle at vertex J.

Final Answer

42\boxed{42^\circ}

Common Mistakes

  • Confusing Arc Subtension: Students often assume opposite angles in the center intersection (vertical angles) are equal to the circumference angles. Always trace the "arms" of the angle back to the circle's edge to identify the arc.
  • Assuming Isosceles Triangles: Unless the problem states the lines pass through the center (radii), do not assume OG=OHOG = OH or OJ=OIOJ = OI. Only the angles subtended by the same arc are guaranteed to be equal.

FAQ

What circle theorem is used to find angle GJO?

The theorem of angles in the same segment is used: inscribed angles subtending the same arc are equal.

How do you identify the arc that subtends angle GJO?

Trace the arms of angle GJO (G and J) along the circumference to find the arc GO. Then look for another inscribed angle opening to the same arc, such as angle GHO.

Why is the final answer 42°?

Angle GJO equals angle GHO because they both subtend arc GO. In triangle OGH, angle GHO = 180° - 117° - 21° = 42°, so GJO = 42°.

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