Question

Solving two right triangles for x and y with tangent

Original question: 16. Find the length of xx, then the length of yy, to the nearest tenth of a metre.

3535^\circ

10 m10\ \mathrm{m}

xx

4848^\circ

yy

Expert Verified Solution

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Key concept: Work through each right triangle separately by matching the known side with the correct tangent relationship.

Step by step

Step 1: Identify the first triangle

The diagram gives a right triangle with a 3535^\circ angle and a side of 10 m10\text{ m}. To find xx, first decide which side the 10 m represents relative to the 3535^\circ angle. In this type of question, the usual approach is to use the trig ratio that connects the known side to the unknown side.

If the 10 m side is adjacent to the 3535^\circ angle and xx is opposite, then

tan35=x10\tan 35^\circ = \frac{x}{10}

so

x=10tan357.0 mx = 10\tan 35^\circ \approx 7.0\text{ m}

Step 2: Use the second triangle

For the second triangle, the 4848^\circ angle is paired with the side length found from the first part, so the next step is to set up the correct trig ratio for yy.

If xx is adjacent to the 4848^\circ angle and yy is the hypotenuse, then use cosine:

cos48=xy\cos 48^\circ = \frac{x}{y}

so

y=xcos48y = \frac{x}{\cos 48^\circ}

Substitute the value of xx:

y7.0cos4810.5 my \approx \frac{7.0}{\cos 48^\circ} \approx 10.5\text{ m}

Step 3: Check the reasonableness

The first answer should be shorter than 10 m if it is an opposite side to a moderate acute angle. The second answer should be larger than xx if it is the hypotenuse. That matches the triangle relationships, so the results are consistent.

Important trig decisions

The main skill in this question is choosing the correct ratio before calculating. Do not start by typing numbers into the calculator randomly. First identify opposite, adjacent, and hypotenuse for each angle. Then select tangent, sine, or cosine based on which sides are involved.

Final answers

x7.0 m\boxed{x\approx 7.0\text{ m}} y10.5 m\boxed{y\approx 10.5\text{ m}}

Pitfall alert

The most common problem here is mixing up which side is opposite, adjacent, or hypotenuse for each angle. Students often reuse the same trig ratio for both parts without re-checking the diagram, which can send the calculation in the wrong direction. Another issue is rounding too early: keep at least one extra decimal place until the end, then round to the nearest tenth of a metre. Also make sure the calculator is in degree mode, because the angles are given in degrees, not radians.

Try different conditions

If the 10 m side were the hypotenuse instead of an adjacent side, the setup would change completely. For example, you might use sin35=x/10\sin 35^\circ = x/10 to find a leg, then use cos48\cos 48^\circ or tan48\tan 48^\circ depending on the new placement of the unknown. If the angles were changed to 3030^\circ and 6060^\circ, the same triangle logic would apply, but the values would be different because each trig ratio depends on the specific angle. The method stays the same: label sides first, then choose the ratio.

Further reading

opposite side, adjacent side, trigonometric ratio

FAQ

How do you choose the correct trigonometric ratio in a right triangle?

First label the side opposite the angle, the side adjacent to the angle, and the hypotenuse. Then choose sine, cosine, or tangent based on which sides are known and which side is unknown.

Why should you avoid rounding too early in trigonometry problems?

Early rounding can change later answers, especially when one calculated side is used in a second triangle. Keep extra decimal places until the final step so the second result stays accurate.

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