Question

Solving a one-step linear inequality with subtraction

Original question: (27) If 1 - 2x ≤ 3, then (a) x ≤ -2 (b) x ≥ -2 (c) x ≤ -1 (d) x ≥ -1

Expert Verified Solution

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Key concept: This question checks whether you can solve a linear inequality by isolating the variable correctly.

Step by step

Start with the inequality

We are given:

12x31 - 2x \le 3

The goal is to isolate xx. Begin by subtracting 1 from both sides:

2x2-2x \le 2

Now divide both sides by -2. Because you are dividing by a negative number, the inequality sign must reverse:

x1x \ge -1

So the correct answer is (d) x1x \ge -1.

Why the sign flips

This is the most important rule in inequality solving. When you multiply or divide by a negative number, the inequality direction changes. That happens because negative scaling reverses the order of numbers on the number line.

If you skipped the sign change, you would incorrectly write x1x \le -1, which is a common error.

Check by substitution

Test the boundary value x=1x = -1 in the original inequality:

12(1)=1+2=31 - 2(-1) = 1 + 2 = 3

Since 333 \le 3 is true, the endpoint works. Now try a value larger than -1, like 0:

12(0)=131 - 2(0) = 1 \le 3

That is also true. Try a value less than -1, like -2:

12(2)=531 - 2(-2) = 5 \le 3

That is false. This confirms that all solutions are numbers greater than or equal to -1.

Key rule to remember

For equations, dividing by a negative is routine. For inequalities, dividing by a negative always reverses the symbol. That one rule decides this problem.

Pitfall alert

A very common mistake is to stop after getting -2x ≤ 2 and then divide by -2 without flipping the inequality sign. That leads to the wrong answer. Another error is to move 1 to the right side as if it were an equation but forget that the original symbol is still an inequality. When the coefficient of x is negative, always check whether the sign must reverse.

Try different conditions

If the inequality were 12x<31 - 2x < 3, the solution would be x>1x > -1 instead of x1x \ge -1 because the strict inequality sign must also flip when dividing by a negative number. If the problem were 1+2x31 + 2x \le 3, then after subtracting 1 you would get 2x22x \le 2, and dividing by positive 2 would give x1x \le 1 without reversing the sign.

Further reading

inequality sign reversal, isolating variables, negative coefficient

FAQ

When do you reverse the inequality sign while solving?

Reverse the inequality sign whenever you multiply or divide both sides by a negative number. In 1 - 2x ≤ 3, dividing by -2 changes the solution to x ≥ -1.

How do you verify the solution to a linear inequality?

Substitute the boundary value into the original inequality and test values on each side of the boundary. This confirms whether the solution should include greater than or equal to, or only greater than.

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