Question

Simplifying a cotangent sine expression using secant

Original question: How to do (i)?

j(x)=(cotx)(sinx)sin2(x1)j(x)=\frac{(\cot x)(\sin x)}{\sin^2(x-1)}

k(x)=(9x+4)34x13xk(x)=\frac{(9^{x+4})\cdot 3^{4x-1}}{3^x}.

(i) Rewrite j(x)j(x) as an expression involving secx\sec x and no other trigonometric functions.

Expert Verified Solution

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Key concept: The expression j(x)=((cot x)(sin x))/sin^2(x-1) is best handled by reducing the cotangent-sine product before worrying about the denominator [1].

Step by step

Key idea

The factor cotxsinx\cot x\cdot \sin x is the first place to simplify in j(x)=(cotx)(sinx)sin2(x1)j(x)=\dfrac{(\cot x)(\sin x)}{\sin^2(x-1)}. Using the identity cotx=cosxsinx\cot x=\dfrac{\cos x}{\sin x}, we get

(cotx)(sinx)=(cosxsinx)(sinx)=cosx.(\cot x)(\sin x)=\left(\frac{\cos x}{\sin x}\right)(\sin x)=\cos x.

So the expression becomes

j(x)=cosxsin2(x1).j(x)=\frac{\cos x}{\sin^2(x-1)}.

If the task specifically asks for an expression involving secx\sec x and no other trigonometric functions, then the numerator can be rewritten as cosx=1secx\cos x=\dfrac{1}{\sec x}. That gives

j(x)=1/secxsin2(x1)=1secxsin2(x1).j(x)=\frac{1/\sec x}{\sin^2(x-1)}=\frac{1}{\sec x\,\sin^2(x-1)}.

Method steps

Start with the definition of cotangent:

cotx=cosxsinx.\cot x=\frac{\cos x}{\sin x}.

Then multiply by sinx\sin x to cancel the denominator. This is the cleanest algebraic simplification in the whole expression, because it removes one trigonometric ratio immediately.

After that, decide how to express the remaining cosine. Since the question requests secx\sec x, use the reciprocal identity

secx=1cosx,socosx=1secx.\sec x=\frac{1}{\cos x}, \quad \text{so} \quad \cos x=\frac{1}{\sec x}.

That leaves an answer with secant only in the simplified numerator.

Final form and identity check

The simplified expression is

j(x)=1secxsin2(x1).\boxed{j(x)=\frac{1}{\sec x\,\sin^2(x-1)}}.

A useful check is to verify that no extra trigonometric functions were introduced unnecessarily. The original product (cotx)(sinx)(\cot x)(\sin x) collapses to cosx\cos x, and cosx\cos x is exactly what can be rewritten with secx\sec x. The denominator sin2(x1)\sin^2(x-1) remains unchanged because the prompt only asks to rewrite the expression, not to expand or convert the shift (x1)(x-1).

Common mistake to avoid

A frequent error is to replace cotx\cot x with secx\sec x. Those are not equivalent: cotx\cot x is a quotient of cosine and sine, while secx\sec x is the reciprocal of cosine. Another mistake is to stop after getting cosx/sin2(x1)\cos x/\sin^2(x-1) even when the instruction asks for secant. The correct final step is to rewrite cosx\cos x as 1/secx1/\sec x, not to force secant into the denominator of the shifted sine term.

If your teacher expects a fully trig-simplified form, keep the denominator as written and only transform the numerator. That respects the original structure while satisfying the requested function form.

Pitfall alert

The place where this expression usually goes wrong is the product (cotx)(sinx)(\cot x)(\sin x), because many students try to simplify the denominator first and never notice that the numerator collapses instantly. Since cotx=cosx/sinx\cot x=\cos x/\sin x, the sinx\sin x cancels cleanly, but if you forget that cancellation you may carry extra factors all the way through and end up with a much messier answer. Another real trap is mixing up reciprocal identities. secx\sec x is the reciprocal of cosine, not sine, so writing sinx=1/secx\sin x=1/\sec x would be incorrect. Also, do not change sin2(x1)\sin^2(x-1) into something like sin2x1\sin^2 x-1; the square applies to the entire shifted angle. Keep the shift intact unless the question explicitly asks for expansion. If the final instruction says “involving sec x,” one safe route is to simplify to cosx/sin2(x1)\cos x/\sin^2(x-1) first and then rewrite cosx\cos x as 1/secx1/\sec x.

Try different conditions

If the numerator were changed to (tanx)(cosx)(\tan x)(\cos x) instead of (cotx)(sinx)(\cot x)(\sin x), the rewritten problem would be: j(x)=(tanx)(cosx)sin2(x1)j(x)=\dfrac{(\tan x)(\cos x)}{\sin^2(x-1)}, and the same strategy would apply, but with a different identity. Since tanx=sinx/cosx\tan x=\sin x/\cos x, the product (tanx)(cosx)(\tan x)(\cos x) simplifies to sinx\sin x, not cosx\cos x. Then the expression would become sinxsin2(x1)\dfrac{\sin x}{\sin^2(x-1)}. If the target still asked for secant only, you would need to decide whether the expression can even be rewritten naturally in terms of secant alone; in many cases it cannot without introducing additional identities or converting back through cosine first. Another useful variation is to replace the denominator with cos2(x1)\cos^2(x-1). Then the expression would be more naturally rewritten using sec(x1)\sec(x-1), showing how the requested target function depends on which trig factor survives after simplification.

Further reading

cotangent identity simplification, secant reciprocal identity, trigonometric expression rewriting

FAQ

How do I simplify a cotangent and sine product before rewriting it with secant?

Use the identity cotangent equals cosine divided by sine, then cancel the sine factor in the product. After that, rewrite cosine as the reciprocal of secant if the problem asks for secant only.

Why should I not change the shifted sine term when rewriting the expression?

Because the prompt only asks to rewrite the expression, not to expand or transform the shifted angle. The squared shifted sine term should stay exactly as written unless the question gives a specific reason to change it.

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