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Right Triangles and Trigonometry

SAT Math· difficulty 4/5

If cos⁡θ=−35\cos\theta=-\frac{3}{5} and θ\theta is in the second quadrant, what is sin⁡θ\sin\theta?

  • A

    35\frac{3}{5}

  • B

    45\frac{4}{5}

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  • C

    −45-\frac{4}{5}

  • D

    −35-\frac{3}{5}

Explanation

sin⁡2θ=1−925=1625\sin^2\theta=1-\frac{9}{25}=\frac{16}{25}. In Q2, sin⁡θ>0\sin\theta>0, so sin⁡θ=45\sin\theta=\frac{4}{5}.

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