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Right Triangles and Trigonometry

SAT Math· difficulty 4/5

From a point on the ground 5050 ft from a tree, the angle of elevation to the top of the tree is 30°30°. What is the height of the tree?

  • A

    503\frac{50}{\sqrt{3}} ft

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  • B

    50350\sqrt{3} ft

  • C

    2525 ft

  • D

    25325\sqrt{3} ft

Explanation

tan⁡30°=h50\tan 30°=\frac{h}{50}, so h=50tan⁡30°=503h=50\tan 30°=\frac{50}{\sqrt{3}}.

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