If sinα=cosβ\sin\alpha=\cos\betasinα=cosβ and both α\alphaα and β\betaβ are acute, what is α+β\alpha+\betaα+β?A90°90°90°check_circleB180°180°180°C60°60°60°D45°45°45°Explanationsinα=cosβ=sin(90°−β)\sin\alpha=\cos\beta=\sin(90°-\beta)sinα=cosβ=sin(90°−β), so α=90°−β\alpha=90°-\betaα=90°−β, i.e., α+β=90°\alpha+\beta=90°α+β=90°.