Nonlinear Functions

SAT Math· difficulty 3/5

What is the horizontal asymptote of y=2x+5y = 2^x + 5?

  • A

    y=7y = 7

  • B

    y=0y = 0

  • C

    y=2y = 2

  • D

    y=5y = 5

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Explanation

The parent function y=2xy = 2^x has asymptote y=0y = 0; shifting up 5 units gives y=5y = 5.

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