What is the vertex of y=(x−3)2+5y = (x-3)^2 + 5y=(x−3)2+5?A(−3,−5)(-3, -5)(−3,−5)B(3,−5)(3, -5)(3,−5)C(−3,5)(-3, 5)(−3,5)D(3,5)(3, 5)(3,5)check_circleExplanationVertex form y=a(x−h)2+ky = a(x-h)^2 + ky=a(x−h)2+k has vertex (h,k)=(3,5)(h, k) = (3, 5)(h,k)=(3,5).