Electrolysis and Faraday's Law

AP Chemistry· difficulty 3/5

A student electroplates copper from 0.50 M CuSO4 onto a clean copper cathode. A constant current of 0.500 A is passed for 30.0 min. The cathode is dried and reweighed; the mass increases by 0.296 g. F = 96,485 C/mol e-. M(Cu) = 63.55 g/mol.

anode (Cu) cathode (Cu) CuSO4 0.50 M 0.500 A 30.0 min, mass gain = 0.296 g

How does the experimental mass of Cu deposited compare to the theoretical mass?

  • A

    Theoretical = 0.296 g; experimental should be 1/2 because Cu^2+

  • B

    Theoretical = 0.148 g; efficiency ~200%

  • C

    Theoretical = 0.296 g; experimental matches within rounding (~100% efficiency)

    check_circle
  • D

    Theoretical = 0.592 g; efficiency ~50%

Explanation

Q = It = 0.500*1800 = 900 C. mol e- = 900/96485 = 9.328e-3. mol Cu = 9.328e-3/2 = 4.664e-3. mass = 4.664e-3 * 63.55 = 0.296 g.

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