Electrolysis and Faraday's Law

AP Chemistry· difficulty 3/5

A student electroplates copper from 0.50 M CuSO4 onto a clean copper cathode. A constant current of 0.500 A is passed for 30.0 min. The cathode is dried and reweighed; the mass increases by 0.296 g. F = 96,485 C/mol e-. M(Cu) = 63.55 g/mol.

If the same charge had instead deposited Ag from AgNO3, what mass of silver would be deposited? (M(Ag) = 107.87 g/mol)

  • A

    1.006 g

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  • B

    0.503 g

  • C

    0.296 g

  • D

    0.148 g

Explanation

Ag+ + e- -> Ag. mol Ag = mol e- = 9.328e-3. mass = 9.328e-3 * 107.87 = 1.006 g.

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