Introduction to Rate Law

AP Chemistry· difficulty 2/5

A student studies the bleaching of crystal violet (CV+) by NaOH using a spectrophotometer at 590 nm. With NaOH in large excess (pseudo-first-order), the absorbance is recorded versus time: t (s): 0 30 60 90 120 150 A: 0.800 0.610 0.464 0.353 0.269 0.205 A plot of ln(A) versus t is linear with slope = -0.00908 s^-1.

Repeating the experiment with twice the [NaOH] gives k_obs = 0.0182 s^-1. What is the order with respect to OH-?

  • A

    Second order

  • B

    First order

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  • C

    One-half order

  • D

    Zero order

Explanation

Doubling [OH-] doubled k_obs, indicating k_obs proportional to [OH-]^1, so first order in OH-.

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