Introduction to Rate Law

AP Chemistry· difficulty 2/5

Students study the reaction S2O8^2- + 2 I- -> 2 SO4^2- + I2 using a clock method (starch indicator + thiosulfate). They measure time t for the blue color to appear in three trials at 25 C with constant ionic strength. Trial 1: [S2O8^2-]=0.040 M, [I-]=0.040 M, t=84 s Trial 2: [S2O8^2-]=0.080 M, [I-]=0.040 M, t=42 s Trial 3: [S2O8^2-]=0.040 M, [I-]=0.080 M, t=42 s

Trial [S2O8] [I-] t (s) 1 0.040 0.040 84 2 0.080 0.040 42 3 0.040 0.080 42

What is the rate law?

  • A

    rate = k[S2O8^2-][I-]

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  • B

    rate = k[S2O8^2-][I-]^2

  • C

    rate = k[S2O8^2-]^2[I-]

  • D

    rate = k[S2O8^2-]

Explanation

Doubling [S2O8^2-] halves t (doubles rate) -> first order. Doubling [I-] also halves t -> first order. Overall rate = k[S2O8^2-][I-].

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