Trial 1: [A]=0.1, [B]=0.1, rate=4×10⁻³. Trial 2: [A]=0.2, [B]=0.1, rate=1.6×10⁻². Order in A is

2 Doubling [A] quadruples the rate → 2² = 4 → second order in A.

Introduction to Rate Law

AP Chemistry· difficulty 3/5

Trial 1: [A]=0.1, [B]=0.1, rate=4\times10⁻³. Trial 2: [A]=0.2, [B]=0.1, rate=1.6\times10⁻². Order in A is

Explanation

Doubling [A] quadruples the rate \to 2² = 4 \to second order in A.

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