AP Chemistry· difficulty 4/5
For N₂O₄(g) ⇌ 2 NO₂(g) at 25 °C, the system starts with 0.10 M N₂O₄. At equilibrium [NO₂] = 0.040 M.
What is Kc?
0.040
0.16
0.020
0.10
Explanation
2x = 0.040, so x = 0.020. [N₂O₄]_eq = 0.10 − 0.020 = 0.080. Kc = (0.040)² / 0.080 = 0.0016/0.080 = 0.020.
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