Heat Capacity and Calorimetry

AP Chemistry· difficulty 2/5

A 200.0 g sample of water is heated by an electric heater that delivers a constant 50 W. Time vs temperature data are recorded.

t (s) T (°C) slope = 0.060 °C/s

What value of c_water (J/g·°C) is implied?

  • A

    12.0 J/g·°C

  • B

    0.060 J/g·°C

  • C

    50 J/g·°C

  • D

    4.17 J/g·°C

    check_circle

Explanation

P = mc(dT/dt). c = P/[m(dT/dt)] = 50/(200·0.060) = 50/12 = 4.17 J/g·°C, matching water's known value.

Want 10 more like this — adaptive to your weak spots?

Related questions