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Heat Capacity and Calorimetry

AP Chemistry· difficulty 4/5

Heating 100. g of iron (c = 0.45 J/g·K) from 25°C to 75°C requires

  • A

    2250 J (q = m c ΔT)

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  • B

    11250 J

  • C

    1125 J

  • D

    4500 J

Explanation

q=mcΔT=(100)(0.45)(50)=2250q = m c \Delta T = (100)(0.45)(50) = 2250 J.

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