To determine the heat of neutralization, a student mixes 50.0 mL of 1.00 M HCl with 50.0 mL of 1.00 M NaOH in a polystyrene calorimeter. Initial temperature of both solutions = 21.5 C. Maximum temperature after mixing = 28.2 C. Assume density 1.00 g/mL and specific heat 4.18 J/(g*C). Heat capacity of the calorimeter is negligible.
If instead 100.0 mL of 1.00 M HCl were mixed with 100.0 mL of 1.00 M NaOH (same initial T), the predicted maximum temperature change is approximately:
- A
halved, about 3.4 C
- B
zero
- C
double, about 13.4 C
- Dcheck_circle
the same 6.7 C
Explanation
Doubling reactant amounts doubles q released and doubles the mass of solution; q/(m*c) gives the same delta T (intensive temperature change).