Introduction to Solubility Equilibria

AP Chemistry· difficulty 3/5

A saturated solution of CaF₂ has [Ca²⁺] = 2.1×10⁻⁴ M.

CaF₂(s) ⇌ Ca²⁺(aq) + 2 F⁻(aq) [Ca²⁺] = 2.1×10⁻⁴ M, [F⁻] = 4.2×10⁻⁴ M Find Ksp

What is Ksp of CaF₂?

  • A

    8.8×10⁻⁸

  • B

    4.4×10⁻⁸

  • C

    3.7×10⁻¹¹

    check_circle
  • D

    1.8×10⁻¹²

Explanation

Ksp = [Ca²⁺][F⁻]² = (2.1×10⁻⁴)(4.2×10⁻⁴)² = (2.1×10⁻⁴)(1.764×10⁻⁷) = 3.70×10⁻¹¹.

Want 10 more like this — adaptive to your weak spots?

Related questions