Introduction to Solubility Equilibria

AP Chemistry· difficulty 2/5

A saturated solution of AgCl gives [Ag⁺] = 1.3×10⁻⁵ M.

AgCl(s) ⇌ Ag⁺(aq) + Cl⁻(aq) [Ag⁺]=[Cl⁻]=1.3×10⁻⁵ M Find Ksp

What is Ksp of AgCl?

  • A

    1.7×10⁻⁵

  • B

    1.7×10⁻¹⁰

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  • C

    1.3×10⁻⁵

  • D

    2.6×10⁻⁵

Explanation

Ksp = [Ag⁺][Cl⁻] = (1.3×10⁻⁵)² = 1.69×10⁻¹⁰ ≈ 1.7×10⁻¹⁰.

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