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Introduction to Solubility Equilibria

AP Chemistry· difficulty 3/5

Ksp(PbI2) = 7.1e-9.

PbI2(s) <-> Pb2+ + 2 I- Ksp = [Pb2+][I-]^2 if solubility = s, [Pb2+] = s, [I-] = 2s Ksp = 4 s^3

What is the molar solubility s in pure water (approximately)?

  • A

    7.1e-9 M

  • B

    2.7e-3 M

  • C

    8.4e-5 M

  • D

    1.2e-3 M

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Explanation

s^3 = Ksp/4 = 1.78e-9; s = cube root ~ 1.2e-3 M.

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