To 1.0 L of buffer (0.20 M acetic acid / 0.20 M acetate), 0.010 mol HCl is added.
What is the new pH?
- A
5.00
- B
4.50
- C
4.74
- Dcheck_circle
4.70
Explanation
pH = 4.74 + log(0.19/0.21) = 4.74 + (-0.044) = 4.70.
AP Chemistry· difficulty 4/5
To 1.0 L of buffer (0.20 M acetic acid / 0.20 M acetate), 0.010 mol HCl is added.
What is the new pH?
5.00
4.50
4.74
4.70
Explanation
pH = 4.74 + log(0.19/0.21) = 4.74 + (-0.044) = 4.70.
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