AP Chemistry · Topic 8.10
Buffer Capacity Practice
Part of Acids and Bases.(SAP-10.D)
Practice questions
6
Sample questions
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Sample 1difficulty 2/5
A student prepares an acetic acid / acetate buffer at pH = 4.74 (pKa of CH3COOH = 4.74). Available stock solutions are 0.500 M CH3COOH and 0.500 M CH3COONa. The student combines 25.0 mL of acetic acid with 25.0 mL of sodium acetate to a total of 50.0 mL. The measured pH is 4.74.
The student adds 5.0 mL of 0.10 M HCl to the 50.0 mL buffer. What is the new pH (approximately)?
- A
5.00
- Bcheck_circle
4.71
- C
4.04
- D
1.30
Why
Initial moles: HA = A- = 0.0125. Add 5.0e-4 mol HCl converts A- to HA: A- = 0.0120, HA = 0.0130. pH = 4.74 + log(0.0120/0.0130) = 4.74 - 0.035 = 4.71.
- A
Sample 2difficulty 3/5
Why does the dashed buffer (lower capacity) change pH faster?
- A
K is smaller for the dashed one
- Bcheck_circle
It contains less HA and A- to absorb added base
- C
It has a different pKa
- D
It is at higher temperature
Why
Buffer capacity scales with the absolute amount of weak acid and conjugate base. Lower amounts mean smaller capacity to absorb added strong acid/base, so pH shifts more.
- A
Sample 3difficulty 3/5
A buffer is generally effective within
- A
Any pH
- B
Only at pKa exactly
- C
pKa ± 5
- Dcheck_circle
pKa ± 1
Why
Within pKa ± 1, ratio of components stays between 1/10 and 10 — workable buffer range.
- A
Sample 4difficulty 3/5
Buffer capacity is greatest when
- A
pH ≪ pKa
- B
[A⁻] ≫ [HA]
- C
Concentration is low
- Dcheck_circle
Components are at equal concentration AND total concentration is high
Why
Both equal ratio (around pKa) and large absolute amounts give the most resilience.
- A
Sample 5difficulty 4/5
A buffer is most effective when
- Acheck_circle
[HA] ≈ [A] and pH ≈ pK
- B
Only acid is present
- C
pH = 7
- D
[HA] >> [A]
Why
Maximum buffer capacity at pH = pK where the buffer can absorb roughly equal amounts of added acid or base.
- A