An NH₃/NH₄⁺ buffer is desired at pH 9.00. Kb(NH₃) = 1.8×10⁻⁵; Ka(NH₄⁺) = 5.6×10⁻¹⁰.
What ratio [NH₃]/[NH₄⁺] is needed?
- A
1.00
- B
1.80
- C
0.25
- Dcheck_circle
0.56
Explanation
pH = pKa + log([NH₃]/[NH₄⁺]). 9.00 = 9.25 + log(r), log r = -0.25, r = 0.56.
Henderson-Hasselbalch Equation
AP Chemistry· difficulty 3/5
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