Henderson-Hasselbalch Equation

AP Chemistry· difficulty 4/5

A buffer with [HA] = 0.10 M, [A⁻] = 0.20 M, pKa = 4.5 has pH

A
$4.8$
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B
$4.0$
C
$4.2$
D
$4.5$

Explanation

pH = 4.5 + log(0.20/0.10) = 4.5 + 0.30 = 4.80.

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