AP Chemistry· difficulty 4/5
A reaction's rate doubles when T rises from 298 K to 308 K. Using ln(k₂/k₁) = (Eₐ/R)(1/T₁ − 1/T₂), Eₐ is roughly
5 kJ/mol
53 kJ/mol
20 kJ/mol
200 kJ/mol
Explanation
ln 2 ≈ 0.693; (1/298 − 1/308)/R ≈ 1.31×10⁻⁵ /(8.314 J/mol·K) → Eₐ ≈ 0.693·R/(1.09×10⁻⁴) ≈ 53 kJ/mol.
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