Steady-State Approximation

AP Chemistry· difficulty 4/5

In a fast pre-equilibrium followed by a slow step, intermediate [I] is expressed by

A
$Always negligibly small$
B
$An equilibrium expression of step 1$
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C
$Cannot be expressed$
D
$Set equal to [reactants]$

Explanation

Pre-equilibrium: K = [I]/[reactants in step 1], allowing [I] to be replaced in the rate-determining step.

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