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Steady-State Approximation

AP Chemistry· difficulty 4/5

Two-step mechanism with a fast pre-equilibrium and a slow second step.

Step 1 (fast eq): A + B ⇌ I Step 2 (slow): I + C -> P Overall: A + B + C -> P Use [I] = K[A][B] in slow-step rate

What is the predicted rate law?

  • A

    rate = k[I][C]

  • B

    rate = k[C]

  • C

    rate = k[A][B]

  • D

    rate = k[A][B][C]

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Explanation

Slow step rate = k2[I][C]. Substituting [I] = K[A][B] gives rate = k2K[A][B][C] = k[A][B][C].

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