For 2 NO₂ → 2 NO + O₂, if [NO₂] decreases at 0.080 M/s, the rate of formation of O₂ is
- A
0.080 M/s
- B
0.020 M/s
- Ccheck_circle
0.040 M/s
- D
0.160 M/s
Explanation
Rate = (1/2)·d[NO₂]/dt = d[O₂]/dt → O₂ rate = 0.040 M/s.
AP Chemistry· difficulty 2/5
For 2 NO₂ → 2 NO + O₂, if [NO₂] decreases at 0.080 M/s, the rate of formation of O₂ is
0.080 M/s
0.020 M/s
0.040 M/s
0.160 M/s
Explanation
Rate = (1/2)·d[NO₂]/dt = d[O₂]/dt → O₂ rate = 0.040 M/s.
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