AP Chemistry· difficulty 2/5
For 2 N2O5 -> 4 NO2 + O2, [N2O5] is consumed twice as fast (in moles) as O2 is produced.
The rate of formation of NO2 equals what multiple of the rate of disappearance of N2O5?
4×
2×
1×
1/2×
Explanation
Stoichiometry: 2 N2O5 -> 4 NO2. So [NO2] forms at twice the rate that [N2O5] is consumed.
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