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Free Energy and Equilibrium

AP Chemistry· difficulty 4/5

At 298 K, a reaction has ΔG∘\Delta G^\circ = −15.0-15.0 kJ/mol. What is K?

  • A

    K≈0.0024K \approx 0.0024

  • B

    K≈1.5K \approx 1.5

  • C

    K≈425K \approx 425

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  • D

    K≈2.5K \approx 2.5

Explanation

ΔG∘\Delta G^\circ = −RTln⁡K-RT\ln K. ln⁡K\ln K = −ΔG∘/(RT)-\Delta G^\circ/(RT) = 15000/((8.314)(298)) = 6.05. K = e6.05e^{6.05} ≈\approx 425.

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